Smoke from the burning of solid fuel gas is calculated

Smoke from the burning of solid fuel gas is calculated
A, theoretical air volume calculation
L = 0.2413 Q / 1000 + 0.5
L: fuel amount of air required for complete combustion theory, the unit is m3 / kg;
Q: fuel of low calorific value, the unit is kJ/kg;
Second, the theory of smoke volume calculation
V = 0.01 (1.867 + 0.7 S + 0.8 C, N) + 0.79 L
V: theory do smoke gas, the unit is m3 / kg;
C, S, N: carbon, sulfur and nitrogen content in the fuel.
L: theoretical air volume
Wet smoke volume calculation theory plus the hydrogen in the fuel, and water content, the coefficients are 11.2, 1.24, respectively

Smoke from the burning of solid fuel gas is calculated
Three, the actual smoke volume calculation
Where V0 = V + L (a - 1)
Where V0: actual dry flue gas emissions, the unit is m3 / kg
A: excess air coefficient, can consult relevant literature material selection.      
According to the above formula, 1 kg of standard coal combustion to produce 7.5 m3, a ton of coal combustion produces 10500 standard cubic meters dry smoke gas.
Smoke from the burning of liquid fuel gas is calculated
A, theoretical air volume calculation
L = 0.203 Q / 1000 + 2.0
L: fuel amount of air required for complete combustion theory, the unit is m3 / kg;
Q: fuel of low calorific value, the unit is kJ/kg;
Second, the theory of smoke volume calculation
V = 0.01 (1.867 + 0.7 S + 0.8 C, N) + 0.79 L
V: theory do smoke gas, the unit is m3 / kg;
C, S, N: carbon, sulfur and nitrogen content in the fuel.
L: theoretical air volume
Wet smoke volume calculation theory plus the hydrogen in the fuel, and water content, the coefficients are 11.2, 1.24, respectively
Three, burning smoke gas produced a tons of heavy fuel oil
According to the above formula, a ton of heavy oil combustion produces 15000 standard cubic meters dry smoke gas.
Smoke from the burning of gas volume is calculated
A, theoretical air volume calculation
L = 0.0476 [0.5 0.5 H2 + CO + 1.5 H2S + ∑ (m + n / 4) CmHn - O2]
L: fuel amount of air required for complete combustion theory, the unit is m3 / m3;
Two, three atomic gas volume calculation
V1 = 0.01 (+ CO + CO2 H2S + ∑ CmHn
Three, flue gas nitrogen volume calculation
V2 + N = 0.79 L / 100
Fourth, water vapor volume calculation
V3 = 0.01 (H2 + H2S + ∑ n / 2 CMHN - O2 + 0.124 d) + 0.0161 L
Five, the smoke volume is calculated
V = V1 + V2, V3 + L (a - 1)
According to the above formula, a cubic meters of natural gas combustion to produce 11 standard cubic meters of smoke volume.